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(O2) rotating in the xy plane about the z axis passing through its center, perpendicular to its length. The mass of each oxygen atom is 2.66 x 10^ -26 kg, at room temperature, and the average separation distance between the two oxygen atoms is 2.02 x 10^ -10 m (atoms treated as point masses).

If the angular speed of the molecule about the z axis is 5.61 x 10^12 rad/s, what is its rotational kinetic energy in units of J?

2006-10-25 07:38:39 · 4 answers · asked by Mariska 2 in Science & Mathematics Physics

4 answers

KE=(1/2)*I*omega^2

I=m*r^2 for each atom, r being half the distance that seperates them, so in total 2*m*r^2

omega= 5.61 x 10^12 rad/s

There you go, you're all set, hope it helps!

2006-10-25 07:43:29 · answer #1 · answered by socrmom 2 · 0 0

All diatomic molecules exist in pairs when alone. It's just a rule you have to get used to. I'm pretty sure the only diatomic molecules are Nitrogen, Hydrogen, Oxygen, Bromine, Fluorine, Iodine, and Chlorine I put Carbon instead of Chlorine, My mistake :/

2016-05-22 13:16:28 · answer #2 · answered by Evelyn 4 · 0 0

Type rotational kinetic energy of oxygen molecule at answers.com .I think hopefully you will get some leads not answers from which you can arrive at the answer of your question.

2006-10-25 07:47:24 · answer #3 · answered by Richard J 6 · 0 0

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2006-10-25 07:48:39 · answer #4 · answered by Anonymous · 0 0

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