2006-10-25 06:52:15 · 5 answers · asked by snclove2001 1 in Education & Reference ➔ Homework Help
l=2+4w
lw=20
w(4w+2)=20
4w^2+2w-20=0
2w^2+w-10=0
w=-1+/-rt(1+80)/4
=8/4=2
l=2+8=10
the dimensions are 10*2
2006-10-25 07:01:12 · answer #1 · answered by raj 7 · 0⤊ 0⤋
Width = 2 and Length = 10
2006-10-25 07:02:48 · answer #2 · answered by Blessed Son 1 · 0⤊ 0⤋
Conditions:
1. the length is 4 times the width plus 2.
so if width is 1, the length is 1(4) + 2 = 6
2. Area must 20 cm square.
W L Area
----------------------------
1 6 (1 multiply 6) = 6 (wrong)
2 10 (2 multiply 10) = 20 (right)
therefore, width = 2 cm, length = 10 cm
2006-10-25 07:07:42 · answer #3 · answered by sendohsan 2 · 0⤊ 0⤋
length = 4*w + 2
area = 20 = length*width
(4w+2)w = 20
4w^2 + 2w - 20 = 0
(2w - 4)(2w + 5)
w = 2 (positive solution)
Check:
Length = 4*w + 2 = 10
Width = 2
10*2 = 20
2006-10-25 06:59:55 · answer #4 · answered by Dentata 5 · 1⤊ 0⤋
if
w=x then
l=4x+2
now,
4x^2+2x=20
thus,x=2
thus,
w=2 and l=10
2006-10-25 07:02:49 · answer #5 · answered by Pravesh 3 · 0⤊ 0⤋