One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F. What was the hourly rate of temperature change?
2006-10-25 06:20:08 · 7 answers · asked by shy l 1 in Science & Mathematics ➔ Mathematics
Ok, the temperature rose from
43°F to 56°F from 2:00 A.M. to 3:00 P.M
So the temperature rose
56 - 43 = 13°F between 2:00 A.m and 3:00 P.M
Now between 2 A.M and 3 P.M., notice the A.M. and P.M., there are 13 hours
2am (1) 3am (2) 4am (3) 5am (4) 6am (5) 7am (6) 8am (7) 9am (8) 10am (9) 11am (10) 12pm (11) 1pm (12) 2pm (13) 3pm
So if the temperature rose 13°F over 13 hours
than 13/13 = 1, or 1°F per hour
2006-10-25 06:42:30 · answer #1 · answered by Clayton A 2 · 0⤊ 0⤋
56 - 43 / (number of hours between 3 PM and 2 AM)
2006-10-25 06:21:59 · answer #2 · answered by gjmb1960 7 · 0⤊ 0⤋
Looks like 1 degree per hour.
2006-10-25 06:30:31 · answer #3 · answered by Wayne W 1 · 0⤊ 0⤋
The hourly rate of temperature change is
1° Fahrenheit per hour
- - - - - - -s
2006-10-25 07:23:18 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
1°F/H
2006-10-25 06:24:43 · answer #5 · answered by catitaa 1 · 0⤊ 0⤋
it has increased by 4
2006-10-25 06:26:43 · answer #6 · answered by Gjseitivkskr 1 · 0⤊ 0⤋
one degree per hour
2006-10-25 06:28:45 · answer #7 · answered by nellie 3 · 0⤊ 0⤋