If a person traveled by car from Lubbock to Midland to San Angelo and back to Lubbock what was the average velocity?
1. 0 because the net displacement is 0
2. 70 mph, because that is the legal speed limit
3. 112.7 km/hr, the legal speed limit in km/hr
4. There is not enough information given.
2006-10-25 06:17:20 · 5 answers · asked by maconheira 4 in Science & Mathematics ➔ Mathematics
4 Not enough information
just because he went from Lubbock and eventually ended up back in Lubbock, does not mean he started and stopped at the same address in Lubbock.
There is no way to know that he averaged the legal limit, there are stop lights, traffic and such where he has to slow down or stop than accelerate up to speed. That means on the highway he would have to be going considerably faster than 70 MPH or 112.7km/hr to compensate. To finish the trip at exactly the maximum average velocity would be very difficult to achieve.
The only conclusion that is most correct is that more information is needed
2006-10-25 06:26:49 · answer #1 · answered by SteveA8 6 · 0⤊ 0⤋
1. 0 because the net displacement is 0
http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/1DKin/U1L1d.html
says this
Now let's try a little more difficult case by considering the motion of that physics teacher again. The physics teacher walks 4 meters East, 2 meters South, 4 meters West, and finally 2 meters North. The entire motion lasted for 24 seconds. Determine the average speed and the average velocity.
The physics teacher walked a distance of 12 meters in 24 seconds; thus, her average speed was 0.50 m/s. However, since her displacement is 0 meters, her average velocity is 0 m/s. Remember that the displacement refers to the change in position and the velocity is based upon this position change. In this case of the teacher's motion, there is a position change of 0 meters and thus an average velocity of 0 m/s.
different question but the point is the same!
2006-10-25 13:29:18 · answer #2 · answered by Bobby B 2 · 0⤊ 0⤋
It is answer 1.
2006-10-25 13:58:49 · answer #3 · answered by Andrew W 4 · 0⤊ 0⤋
1.true because velocity=displacement/time
2.false
3.false
4.false
2006-10-25 13:20:49 · answer #4 · answered by raj 7 · 0⤊ 0⤋
d = Distance
r = rate
t = time
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d = rt
d/t = rt/t
d/t = r
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The answer is 1 .
- - - - - - - s
2006-10-25 14:30:59 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋