the length of rectangle is 1 foot more than three times the width. if the area is 52ft, find the dimensions?

Answer 1

length = 3*width + 1
area = width * length
x(3x + 1) = 52
3x^2+x-52 = 0
(3x + 13)(x-4)
x = 4

width = 4
length = 13

Answer 2

Let the width of the rectangle be x ft.Therefore,the length is 3x+1 ft, According to the problem, x(3x+1)=52 or 3x^2+x=52 =>3x^2+x-52=0 =>.3x^2+13x-12x-52=0 =>x(3x+13)-4(3x+13)=0 => (x-4) (3x+13)=0 .=> x-4=0 0r 3x+13=0 Thereforex=4 or -13/3.Disregarding negative value of x (as the breadth/length cannot be negative),we get the breadth of the rectangle to be 4ft. and the length is (3*4+1 or )13 ft.

Answer 3

A=l times w

sooo...let w=width and l=3w +1

Equation is: w(3w+1) = 52

Solve for w, then plug in to get length.