12x^2+6X-60
2006-10-25 05:55:15 · 11 answers · asked by sttr2br 1 in Science & Mathematics ➔ Mathematics
12x^2+6x-60
=6(2x^2+x-10)
=6[2x^2-4x+5x-10]
=6[2x(x-2)+5(x-2)]
=6{(x-2)(2x+5)}
2006-10-25 05:59:50 · answer #1 · answered by raj 7 · 0⤊ 0⤋
12x^2+6x-60........original equation, try to find a number that all three of them have in common
6*(2x^2+x-10)......all numbers have 6 as common factor
(2x+5)(x-4).......factor of (2x^2+x-10)
6*(2x+5)(x-4)........final answer
2006-10-25 06:17:17 · answer #2 · answered by Anonymous · 0⤊ 0⤋
First take out the common factor 6
12x² + 6x - 60
6(2x² + x - 10)
6(2x + 5)(x - 2)
-- - - - - - - - - - s-
2006-10-25 08:01:37 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
1. first take out 2 common from the equ it becomes
2.6x^2+3x-30
3.find the factors of 6*30 ----->3*2*5*6
4. so u can splllit the mid term ie. 3x as 15x-12x
5.6x^2+15x-12x-30
6.Now group first two term and last two term and take out common factors
7.3x(2x+5)-6(2x+5)
8.again take out 2x+5 common
9.(2x+5)(3x-6) is the requ. answer
2006-10-25 06:07:29 · answer #4 · answered by Sudhir P 1 · 0⤊ 0⤋
peace of cake.
12x^2+6X-60 = 2*(x-10/4)*(x+2)
2006-10-25 08:53:36 · answer #5 · answered by trankssj 1 · 0⤊ 0⤋
factor out 6
6 (2x^2 + x - 10)
factor the term
6 (2x + 5) (x - 2)
that's as far as you can go on this one
2006-10-25 07:45:45 · answer #6 · answered by Doug R 5 · 0⤊ 0⤋
= (2x+5)(x-2) or X= -5/2, 2
2006-10-25 06:00:32 · answer #7 · answered by Jambi 2 · 0⤊ 0⤋
6*(x - 2)(2x + 5)
2006-10-25 05:58:37 · answer #8 · answered by DavidK93 7 · 0⤊ 0⤋
6*(x - 2)(2x + 6)
2006-10-25 06:00:57 · answer #9 · answered by Rita Z 2 · 0⤊ 0⤋
FACTOR OUT 6 THEN USE THAT EQUATION ABC, I FORGOT WHAT IT IS CALL, SORRY,
2006-10-25 05:58:54 · answer #10 · answered by amy e 2 · 0⤊ 0⤋