you have equation y=2x+b, right?
so you just plug in the point for x and y:
y=2x+b
-8=2(2)+b
-8=4+b
b=-12
Hope that helps!
2006-10-25 03:38:55
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answer #1
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answered by D 3
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if y=2x+b passes through the point (x=2 , y=-8)then -8 = 2*2+b = 4+b (otherwise the line would not pass through that point because x=2,y=8 would not be one of the solutions to the equation).
subtract 4 from both sides and you get -12=b
2006-10-25 03:51:45
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answer #2
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answered by Anonymous
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As the point lies on the line, the equation must be true for that point too. So just set the coordinates in the equation an solve:
-8 = 2*2 + b and you get that b = -8 - 4 = -12
That really is not dificult !!
2006-10-25 03:44:02
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answer #3
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answered by charlie 1
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given points: (2,-8)
ur equation is: y=2x+b
use ur given points 2 is x and -8 is y
org. equation: y= 2x+b
-8= 2(2)+b
-8=4+b(subtract 4 from both sides)
-8-4=4-4+b(4-4 cancel out)(-8-4 is -12)
-12=b is ur answer
check ur answer start with org. equation
y=2x+b
-8=2(2)-12
-8=4-12
-8= -8
2006-10-25 03:52:40
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answer #4
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answered by sweet_p1993 2
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you plug in your given point into the equation so,
y=2x+b
-8=2(2)+b
-8=4+b
-4 -4
------------
-12=b
2006-10-25 03:40:10
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answer #5
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answered by Anonymous
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The slope-intercept form:
y=mx+b
For this problem, plug in (2,-8) into the x and y values:
-8=2(2)+b
-8=4+b
b=-12
Check:
-8=2(2)-12
-8=4-12
-8=-8
I hope this helps!
2006-10-25 04:04:03
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answer #6
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answered by Anonymous
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b = -12, x=2, y=18
2006-10-25 03:43:35
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answer #7
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answered by LoonyToom 2
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Simply plug in your point to find b:
y = 2x + b, so
-8 = 2(2) + b.
b = -12.
2006-10-25 03:39:17
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answer #8
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answered by steiner1745 7
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Joel this is Zach your not going to pass Winers class anyway thus you don't need to do you homework............Try the Fair line method.
2006-10-25 03:45:18
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answer #9
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answered by Anonymous
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HI
2006-10-25 03:45:14
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answer #10
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answered by J W 2
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