2006-10-25 03:32:38 · 9 answers · asked by ned f 1 in Science & Mathematics ➔ Mathematics
Yep "minus t" [-t] is the answer.
2006-10-25 03:39:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Treat this as -1/2 x t^2
so -1/2 is the constant.
The rest is in the form t^n and to differentiate it is nt^(n-1)
Differentiate t^2, bring down the 2 and reduce the power by 1
You have -1/2 x 2 x t^(2-1)
or -1/2 x 2t = -t
2006-10-26 15:29:57 · answer #2 · answered by Bill N 3 · 1⤊ 0⤋
To differentiate this with respect to t, what you have to do is reduce the power of t by 1, and mutliply (-t)/2 by the original power of t, i.e.2. Thus, you get the result
d(-(t^2)/2/dt= 2(-t/2)= -t.
Hope this helps!
2006-10-25 12:15:10 · answer #3 · answered by friendly_220_284 2 · 0⤊ 0⤋
Isn't it just -1/2 * t^2 ?
so -t
2006-10-25 10:38:07 · answer #4 · answered by Anonymous · 1⤊ 0⤋
d(-t^2/2)/dt = -2t/2 = -t
{dy/dx = nx^(n-1)}
i hope that this helps
2006-10-26 05:59:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
-1/2(2t)
-t
2006-10-25 11:25:06 · answer #6 · answered by arpalu69 1 · 0⤊ 0⤋
-2t/2 = -t.
2006-10-25 10:45:00 · answer #7 · answered by steiner1745 7 · 0⤊ 0⤋
The answer is "t"
2006-10-25 10:38:22 · answer #8 · answered by Zam 2 · 0⤊ 1⤋
-t
2006-10-25 10:44:21 · answer #9 · answered by Anonymous · 0⤊ 0⤋