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a. An individual that has the genotype AabbCcDd is crossed to one with the genotype AaBbCCdd. Assuming that these genes are unlinked, what fraction of the offspring will have the genotype AAbbCCdd?

b. Assume that in each case the dominant allele is represented by the upper case letter. What fraction of the offspring will exhibit the phenotype of all four dominant alleles?

2006-10-25 03:15:32 · 1 answers · asked by Ashi 2 in Science & Mathematics Biology

1 answers

The chances of each genotype are:
AA - 25%
Aa - 50%
aa - 25%
Bb - 50%
bb - 50%
CC - 50%
Cc - 50%
Dd - 50%
dd - 50%

so... AAbbCCdd has a 43.75% chance of occuring
and all 4 dominant phenotypes has a 68.75% occurence.

2006-10-25 04:52:52 · answer #1 · answered by Nikoru 4 · 1 0

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