What is the pressure of the gas? , What volume does the gas occupy?, How many moles of gas are collected?

Question

A 37.7mL volume of an unknown gas is collected over water at 19 degrees C and a total pressure of 770 torr. The mass of the gas is 68.6mg.

Answer 1

if you are looking for moles use the ideal gas law PV=nRT
the things to remember about the law though are
V is in liters so convert
P is in atmospheres so convert
R is the gas constant 0.08206
n is the moles of particles
T is in Kelvin so convert
so n=(0.0377*1.041)/(0.08206*292)

Answer 2

As you put it your problem is not of the kind of simply using Gas Ideal Law but Adsorption isotherms.

What I do not is what is the value of the constant K required to compute the concentration of gas adsorbed and therefore number of moles, volume occupied by gas and pressure on the water.

I found the Freundlich isotherm used for gas adsorbates:

x/m = KP^(1/n) where: K,n = constant for each pair adsorbate - adsorbent
m = mass of water
x = fraction mass of gas adsorbed in water
P = pressure of gas


Let me continue...

Answer 3

be conscious: i've got self belief you first ought to be sure the moles of hydrogen you made out of the reaction, then you definitely would be responsive to the quantity of this quantity of hydrogen (under the T & P circumstances you listed), then you definitely'll discover the quantity of one mole at those circumstances and finally normalize to a minimum of one mole @ STP to get the respond. the subject is you checklist magnesium in cm, no longer grams, so i do no longer be responsive to how lots you used (by way of weight).

Answer 4

PV=nRT