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what would be the derivative of

V=(1/3) pi h^2 (3R-h)


thanks

2006-10-25 02:48:30 · 5 answers · asked by leksa27 2 in Science & Mathematics Mathematics

5 answers

dV/dh = pi*h(2R-h)

Capital R is traditionally a constant, so I'm guessing its with respect to h.

2006-10-25 02:57:28 · answer #1 · answered by Nature_Boy 2 · 0 0

you need to specify with respect to what variable you want to differentiate

V=(1/3) pi h^2 (3R-h)
=pi h^2 R-(1/3)pi h^3

if you need dV/dh then the answer is
2pi R h-pi h^2
if you need dV/dR then the answer is
pi h^2

2006-10-25 09:56:18 · answer #2 · answered by cmadame 3 · 0 0

It depends on what derivative you want, dV/dh, or dv/dR.

If it is dV/dRr,then it is simply pi h^2.

if it is dV/dh, then it is 2 pi R h -pi h^2

2006-10-25 10:03:15 · answer #3 · answered by ironduke8159 7 · 0 0

first multiply it out.....
1/3pi*3R*H^2-1/3pi*h^3
simplify:
pi*R*(h^2)-1/3pi*(h^3)
then do derivative and it is:
2pi*R*h-pi*(h^2)
can be written as:
pi*h(2R-h)
You wanted it with respect to h, right?
If with respect to R, then its just pi*h^2

Hope that helps!

2006-10-25 09:55:31 · answer #4 · answered by D 3 · 0 1

Derivative with respect to which variable, h or R?

2006-10-25 10:54:38 · answer #5 · answered by steiner1745 7 · 0 0

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