How do you find the x and y?

Question

3x - 1y = -6
-2x - 3y = -7

Answer 1

The easiest way to do it is to multiply the first equation by 2 and the second by 3, then add them together:

6x - 2y = -12
-6x - 9y = -21
-------------------
0x - 11y = -33

y = 3
x = -1 (get this by substituting y back into either equation above)

Answer 2

3x - 1y = -6 - - - - - - -Equation 1
- 2x - 3y = - 7 - - - - - Equation 2

- - - - - - - - - - - - - - -

Multiply equation 1 by - 3

-3(3x) - ( -3)(1y) = -3(-6)

- 9 - (-3y) = 18

- 9 + 3y = 18 The new equation 1

- - - - - - - - - - - - - - -

- 9x + 3y = 18

-2x - 3y = - 7
- - - - - - - - - -
- 11x = 11

- 11x/-11 = 11/- 11

x = - 1

The answer is x = - 1

Insert the x value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - -

3x- 1y = - 6

3( - 1) - 1y = - 6

-3 - 1y = - 6

-3 - 1y + 3 = - 6 + 3

- 1y = - 3

- 1y/- 1 = - 3/ - 1

y = 3

The answer is y = 3

Insert the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - -


Check for equation 1

3x -1y = - 6

3( -1) -1(3) = - 6

-3 - 3 = - 6

- 6 = - 6

- - - - - - - - - - - - - - - - - - - - -

Check for equation 2

- 2x - 3y = - 7

-2(- 1) -3(3) = - 7

2 - 9 = - 7

-7 = -7

- - - - - - - - - - - - - - - - - -

The solution set is { -1, 3 }

- - - - - - - -s

Answer 3

Multiply the first equation by 3
3*(3x - 1y = -6) = (9x - 3y = -18)
Subtract the 2nd equation from the above equation.
Yuo will obtain the eq (11x = -11)
Therefore x = -1
Substitute value of x in the 2nd eq and find value of y
-2(-1) - 3y = -7
therefore y = 3

Answer 4

from first equation
y=6+3x

substitute y inthe second equation yield
-2x-3(6+3x)=-7
-11x=11
so x=-1
and y=6+3x=3

check the answer
3x - 1y = 3(-1) - 1(3)=-6
-2x - 3y = -2(-1) - 3(3) = -7

so the answers are x=-1 & y=3

Answer 5

times the top one by 3 to get

9x - 3y = -18
-2x - 3y = -7

subtract the y's ( -3 - -3 = 0)

9x = -18
-2x = -7

therefore

(9 - -2)x = -18 - -7

11x = -11

x = -1

substitute for x into the first equation

9x - 3y = -18
9(-1) - 3y = -18
-9 - 3y = -18

add 9 to both sides

-3y = -9
3y = 9

y = 3

therefore

x = -1
y = 3

Answer 6

3x - y = -6 => y = 3x + 6

-2x - 3(3x + 6) = -7
-2x - 9x - 18 = -7
-11x = 11
x= -1 and y = 3(-1) + 6 = 3

Answer 7

3x=-6+y (add y both sides)
x= (-6+y)/3 (divide by 3 both sides)

therefore: substiture the above eqaution into the second equation
-2((-6+y)/3) -3y=-7
(12-2y)/3 -3y = -7 ( multiply numerator of fraction by -2)

12-2y-9y= -21 (Multiply both sides by 3)
-11y=-33 (minus 12 both sides)
y=3 (multiply by -1 and divide by 3 both sides)

using this y value you solve for x

3x-1y=-6
3x-1(3)=-6
3x-3= -6
3x=-3 (add three both sides)
x= -1 (divide by 3)

Answer 8

3x - 1y = -6 [x2] = 6x-2y = -12 than eliminates.
-2x - 3y = -7 [x3] = -6x - 9y = -21
----------------------------------------------------------+
you got -11y = -33
y = 3 ----> x = -1 (y result substitute to anyequation above and you got the x result)
thnx.

Answer 9

3x-1y=-6........................(1)x2=> 6x-2y=-12
-2x-3y=-7......................(2)x3=> -6x-9y=-21
(+)
-------------------------------------------------------
-11y=-33
=>y=3
putting the value y= -3 in eqation 1, we get,


3x - 1x(3)=-6
3x=-6+3
=>x= -1

Answer 10

u solve them simutaneously. x is -1 and y is 3