general ecuation
x = [-b +/- sqrt(b^2-4ac)]/2a
x = {-(-4) +/- sqrt[(-4)^2 - (4)(2)(1)]} / 2(2)
x = [4 +/- sqrt(16-8)] / 4
x = [4 +/- 2.828] / 4
x1 = (4 + 2.828) / 4 = 1.707
x2 = (4 - 2.828) / 4 = 0.293
2(1.707)^2 - 4(1.707) + 1 = 0
5.828 - 6.828 + 1 = 0
2(0.293)^2 - 4(0.293) + 1 = 0
0.172 - 1.172 + 1 = 0
I hope this helps
2006-10-24 13:15:47
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answer #1
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answered by alexandrobilan 2
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denbronco is wrong, alexandro is right - use the quadratic formula.
If you re-multiply the "factors" denbronco came up with [(2x-1)(x-1)], you end up with 2x^2-3x+1, which is NOT your original equation.
2006-10-25 09:08:16
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answer #2
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answered by homeschoolmom 5
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Factor it.
2X^2-4X+1=0
(2X-1)(x-1)
Now you have 2 equations.
2X-1=0
2X=1
X1=1/2 or .5
X-1=0
X=1
X2=1
2006-10-24 20:31:06
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answer #3
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answered by Anonymous
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2 +/- square root of 2
2006-10-24 19:38:10
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answer #4
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answered by Anonymous
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i think its (2x-1)^2
and x=1/2 well i guess this isnt help, just the answer, but yeah :)
2006-10-24 19:40:28
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answer #5
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answered by Anonymous
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denbroncos got it right
2006-10-24 21:58:37
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answer #6
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answered by chompsey 1
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try math.com
2006-10-24 19:43:02
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answer #7
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answered by JaneDivided 4
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