2006-10-24 12:30:50 · 7 answers · asked by sexy sunbather 1 in Education & Reference ➔ Home Schooling
general ecuation
x = [-b +/- sqrt(b^2-4ac)]/2a
x = {-(-4) +/- sqrt[(-4)^2 - (4)(2)(1)]} / 2(2)
x = [4 +/- sqrt(16-8)] / 4
x = [4 +/- 2.828] / 4
x1 = (4 + 2.828) / 4 = 1.707
x2 = (4 - 2.828) / 4 = 0.293
2(1.707)^2 - 4(1.707) + 1 = 0
5.828 - 6.828 + 1 = 0
2(0.293)^2 - 4(0.293) + 1 = 0
0.172 - 1.172 + 1 = 0
I hope this helps
2006-10-24 13:15:47 · answer #1 · answered by alexandrobilan 2 · 0⤊ 0⤋
denbronco is wrong, alexandro is right - use the quadratic formula.
If you re-multiply the "factors" denbronco came up with [(2x-1)(x-1)], you end up with 2x^2-3x+1, which is NOT your original equation.
2006-10-25 09:08:16 · answer #2 · answered by homeschoolmom 5 · 0⤊ 0⤋
Factor it.
2X^2-4X+1=0
(2X-1)(x-1)
Now you have 2 equations.
2X-1=0
2X=1
X1=1/2 or .5
X-1=0
X=1
X2=1
2006-10-24 20:31:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2 +/- square root of 2
2006-10-24 19:38:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i think its (2x-1)^2
and x=1/2 well i guess this isnt help, just the answer, but yeah :)
2006-10-24 19:40:28 · answer #5 · answered by Anonymous · 0⤊ 0⤋
denbroncos got it right
2006-10-24 21:58:37 · answer #6 · answered by chompsey 1 · 0⤊ 0⤋
try math.com
2006-10-24 19:43:02 · answer #7 · answered by JaneDivided 4 · 0⤊ 0⤋