I am wondering if two 4" hydrulic pistons have the same power as one 8" inch piston? My brother says that one 8" piston is stronger than two 4's? I think it they should be about the same, although there might be a difference in the size of hydraulic pumps needed? Thanks
2006-10-23 06:28:47 · 6 answers · asked by myidbob55 1 in Science & Mathematics ➔ Engineering
It's the area that counts, not the diameter.
8^2 = 64
2*4^2 = 32
So, an 8 in diam piston has twice the area of two 4 in diam pistons. Hence since
force = pressure * area,
The single large piston exerts twice the force for the same pressure. You now know half of the subject of hydraulics.
2006-10-23 06:37:41 · answer #1 · answered by modulo_function 7 · 1⤊ 0⤋
Greetings!
Your brother is correct. Diverting the energy from the source to two different destinations lessens the amount of thrust the piston is able to produce.
The power you speak of is not the piston but the pump. The piston acts as a direct reaction from the energy produced by the pump.
Good Luck
2006-10-23 13:32:36 · answer #2 · answered by Anonymous · 0⤊ 1⤋
It would take four 4 inch pistons because of the element of the square of the radius.
pi = 3.14
r = 2"
(3.14) x (2")2 = 12.56
12.56 x 2 =
25.12insq = 2 four inch pistons
3.14 X (4")2 =
50.24 = one 8 inch piston
2006-10-23 13:36:38 · answer #3 · answered by FrogDog 4 · 1⤊ 0⤋
Hi. If you assume equal pressure the piston(s) with the most surface area have the most power. Solve for both areas.
2006-10-23 13:32:09 · answer #4 · answered by Cirric 7 · 1⤊ 0⤋
No, the power generated is proportional to the square of the diameter.
2006-10-23 13:33:13 · answer #5 · answered by Anonymous · 1⤊ 0⤋
both can procuce the same force
2006-10-24 04:18:09 · answer #6 · answered by gussie r 3 · 0⤊ 0⤋