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11111111111000000000000000000000

(no.1=11, no.0=21)

2006-10-21 17:28:32 · 3 answers · asked by Anonymous in Science & Mathematics Engineering

3 answers

The 8-bit exponent field is all one-bits, so it's not a normal number. It's either minus infinity, or a representation of "Not-a-Number". Visit the web site to learn more.

2006-10-22 10:50:43 · answer #1 · answered by Anonymous · 0 0

The IEEE Standard for Binary Floating-Point Arithmetic (IEEE 754) is the most widely-used standard for floating-point computation, and is followed by many CPU and FPU implementations. The standard defines formats for representing floating-point numbers (including negative zero and denormal numbers) and special values (infinities and NaNs) together with a set of floating-point operations that operate on these values. It also specifies four rounding modes and five exceptions (including when the exceptions occur, and what happens when they do occur).

2006-10-21 18:05:33 · answer #2 · answered by Dark Knight 3 · 0 0

first bit is the sign bit
8 bits of biased exponent
remainder of bits is magnitude

2006-10-21 19:22:02 · answer #3 · answered by arbiter007 6 · 0 0

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