This may be a simple question to some, but I'm so lost... I'm trying to determine what kind of adapter I need. I already know I need 12v 1a... The diagram on the device shows the negative on the outside and positive on the inside... as such:
(-)----(o-----(+)
Is this a standard 12v DC? AC/DC?
How do you read it to determine what exact polarity you need (is this the devices polarity or that required of the power prong?), and how can you determine this simply by looking at the information given on an adapter?
2006-10-18 09:19:05 · 5 answers · asked by kallistos 2 in Consumer Electronics ➔ Other - Electronics
That would be 12V DC; if it was AC it should say so, or maybe have a symbol like ~ to denote alternating current.
The correct AC adapter will have a diagram with the same polarity.
Your unit looks to have a standard polarity, since it's the same as the old Dell laptop adapter I'm holding (model APAC-1, 12V 2.0 A). Where you can run into problems is in the connector. I had to install a different size connector on this Dell supply so that I could use it to power an HP 3400C scanner. And if you can't find an adapter with exactly the same current rating (1 amp), it is OK to use an adapter with a higher current rating.
2006-10-18 09:35:48 · answer #1 · answered by Wombat 4 · 4⤊ 0⤋
Somewhere on the casing, DC adapters indicate the polarity of the different contacts on the device-end plug, as well as the input AC voltage range, frequency, and the output DC voltage and current.
2006-10-18 09:22:31 · answer #2 · answered by Joe Rockhead 5 · 0⤊ 0⤋
as a results of fact of ac indicators could be used in long distance transmissions.. on a similar time as DC can not.. The loss in ac could be recovered by way of only including a lead or lag circuit.. on a similar time as loss in DC can not be recovered.. And as you have observed, the go portion of the twine will boost as a results of fact the present transmitted will boost, DC heavily isn't affordable as ac.. occasion: a undeniable twine can carry a optimal quantity of modern. Now, making use of DC, this could finally end up making use of limited quantity of DC which losses can not be recovered. Now making use of ac, a intense modern sign could be switched over to a intense voltage-low modern sign which losses could be recovered and this sign could be switched over back to a low voltage-intense modern sign..
2016-12-08 16:58:47 · answer #3 · answered by ? 4 · 0⤊ 0⤋
The "o" in your diagram represents the center of the tip. So it's center postitive.
AC has no polarity. So it's DC 12V @ 1000mA (1 A)
2006-10-18 09:34:34 · answer #4 · answered by Anonymous · 2⤊ 0⤋
It would depend on whether the device is Back in Black or on The Highway to Hell.
2006-10-18 09:21:07 · answer #5 · answered by Trollbuster 6 · 0⤊ 3⤋