2006-10-11 15:19:30 · 20 answers · asked by Anonymous in Society & Culture ➔ Religion & Spirituality
I think he'd sell health freak food.
Life's Lovely! Love & Live Life!
2006-10-11 16:01:05 · answer #1 · answered by Starreply 6 · 3⤊ 0⤋
Gosh I hope so. I mean, I wouldn't want the beer or the onion rings and I don't like that stuff, but if it'll make other people happy then yeah, let's keep it all and I'll just snack on pizza. Could God possibly include some curly fries and cheese sticks?
2006-10-15 16:53:37 · answer #2 · answered by Anonymous · 0⤊ 0⤋
God has all the restaurants and everything in this world. He wants us to enjoy all of it. Only when some drunk , drinks too much beer, is when trouble starts. Everyone has a spirit inside that tells us when to stop. Not listening to your inner spirit is when we get in trouble. God wants us to enjoy it all, but in an intelligent way.
2006-10-11 22:26:39 · answer #3 · answered by Norskeyenta 6 · 0⤊ 0⤋
God owns all the restaurants, He lets humans manage them.
So, yes.
And the onion rings are out of this world!
2006-10-11 22:26:29 · answer #4 · answered by megmom 4 · 0⤊ 0⤋
If God had a restaurant, it would have anything you could want. The best foods and drinks for free. It would be the place to be, I only wish there was one on earth for us.
2006-10-11 22:39:57 · answer #5 · answered by pears_pal 1 · 0⤊ 0⤋
He would sell a cup of honesty, a bowl of Intergity and a Salad Bar of MORALS..
2006-10-11 22:22:43 · answer #6 · answered by Heather b 3 · 0⤊ 0⤋
Only in your world.
2006-10-11 22:21:33 · answer #7 · answered by Bad Cosmo 4 · 0⤊ 0⤋
Man I hope so those are ny favorite food groups
2006-10-11 22:20:39 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Sure why not. He would surely like us to come to be with him sooner than later and the suffering for those who will die in their sins be over.
2006-10-11 22:21:56 · answer #9 · answered by Makemeaspark 7 · 2⤊ 0⤋
More importantly would it be located at the end of the universe?
2006-10-11 22:23:30 · answer #10 · answered by jedi1josh 5 · 2⤊ 0⤋