I just want to know what a pair of shoes cost in Bangkaok, Thailand, in US dollars.Just a regular pair of sneakers.
2006-10-11 13:05:09 · 11 answers · asked by jennifer a 1 in Travel ➔ Asia Pacific ➔ Thailand
5 usd if no brand, but almost normal price if branded and genuine
2006-10-11 23:15:19 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Branded ones found in the major shopping centers are probably slightly cheaper than back home. I guess one does not shops at Bangkok for these.
The copy ones (of the branded stuff) are available, anything from Bahts 500 - 1000.
The locally made ones (not trying to imitate anyone) can goes from Bahts 99 upwards. Bahts 300 can fetch you a reasonably good pair of sneakers.
* US$1=38 Bahts (approximate)
2006-10-11 14:48:11 · answer #2 · answered by TK 4 · 1⤊ 0⤋
Height: 5'4" Shoe size: 7 1/2 Clothes size: 3/5
2016-03-28 05:33:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You can get very cheap shoes there. But in my experience if they get wet then you will have to throw them away. And it sure does ran like a flood some nights in Bangkok..the number of times I have been knee deep in water...
2006-10-11 20:35:11 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The cheapest pair i have seen is about 100 baht which is about 3 US dollars.
2006-10-11 13:14:49 · answer #5 · answered by naychan 2 · 1⤊ 0⤋
@ siam square and MBK
they should be about 100-300฿
for a pair, not branded not quality stuff, but most of teenager use it cuz it's cheap and full of design
my friends always go there for shopping
[included guys' and girls' shoes]
2006-10-14 08:22:35 · answer #6 · answered by Obi 2 · 0⤊ 0⤋
Night market or Saturday market about 2-4 dollars, if you bicker just a little.
2006-10-12 19:21:03 · answer #7 · answered by EMAILSKIP 6 · 0⤊ 0⤋
A mans' head. That and 5 dollars.
2006-10-11 13:12:57 · answer #8 · answered by General X 3 · 0⤊ 1⤋
if it was made in china, $3 at least.
2006-10-11 13:17:12 · answer #9 · answered by lnfrared Loaf 6 · 0⤊ 0⤋
5dollars
2006-10-11 13:06:47 · answer #10 · answered by Anonymous · 0⤊ 0⤋