this is PSAT question. (practice test)
#31) each of the 24 students in achemistry class needs to have exactly 120 milliliters of solution in a beaker. if the teacher uses a bottle containing 3 liters of the solution to fill each beaker without spilling, how many milliliters of solution will the teacher have left in the bottle after filling the beakers? (1 liter = 1000 milliliters)
- it's not very difficult but i'm very stupid so i don't know this! please tell me the answer with explanation! thanx
2006-10-10 16:54:10 · 9 answers · asked by ashylnn 1 in Education & Reference ➔ Other - Education
I'm sure you're not stupid. This kind of thing is just very frustrating.
First step: determine how many mL solution is needed by all the students. Multiply the # of students by the necessary mL per beaker.
24 students * 120 mL solution/student = 2880 mL solution
Since we know that 1 L = 1000 mL of solution, we can also determine the total mL of solution the teacher has.
3 L * 1000 mL/L = 3000 mL
Now simply subtract:
3000 mL - 2880 mL = 120 mL solution remaining.
You might check the math, but I think my numbers are correct. Does this sequence make sense?
Good luck!
2006-10-10 17:01:46 · answer #1 · answered by Kwa Nini Hufahamu? 4 · 1⤊ 0⤋
The teacher will be left with just enough solution to fill her own beaker! Here's how:
24 students * 120 = 2880 ml. 3 ltrs = 3 * 1000 = 3000 ml
3000 - 2880 = 120 ml.
2006-10-10 17:03:31 · answer #2 · answered by Krishna 4 · 1⤊ 0⤋
Since there are 24 students and they have120 milliliters , you do this:
24*120=2880
3 liters =3000 milliliters
the teacher will pour them all to the students' beaker, so you do this:
3000-2880=120
Thus, there will be 120 mililiters left in the the teacher's bottle
2006-10-10 17:01:41 · answer #3 · answered by K 3 · 1⤊ 2⤋
Fairly simple: 3000mL - (24*120mL)
3000 - 2880 = 120 mL
So, the teacher would have enough left to do the same expirement for herself. Then, multiplying back out, 25 (including the one for the teacher) * 120 = 3000mL.
2006-10-10 17:17:20 · answer #4 · answered by Deirdre H 7 · 1⤊ 0⤋
24 students x 120 mm =
2880 mm needed for all students
3 L = 3000mm
3000mm - 2880mm = 120mm
Teach will have 120 mm left
2006-10-10 17:02:22 · answer #5 · answered by Mr.Moo 4 · 1⤊ 0⤋
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2016-10-02 04:27:57 · answer #6 · answered by ? 4 · 0⤊ 0⤋
120*24=2880mL
3000mL-2880mL=120mL
Basically, find out how much solution will be needed for the entire class (2880mL) and subtract that from the total amount of solution (3000mL).
2006-10-10 17:04:30 · answer #7 · answered by Sheila 3 · 1⤊ 0⤋
Wats a beaker??
2006-10-10 17:01:34 · answer #8 · answered by yahwhoon 4 · 0⤊ 2⤋
its 120 :)
2006-10-10 17:03:56 · answer #9 · answered by bamdix 2 · 1⤊ 0⤋