O(a)K ........we can figure this out together. Maple it out of my hat......but I'm determined to find this answer. It might not be the most Poplar answer, but even a Dog-wood not ignore this one.
Ok so.....give me a Pear of numbers and I'll conifer with my mathematical teacher friends and see what they can come up with. I knew I shouldn't just read all the time.......but it is so hard for me to branch out. But I'll go out on a limb this time.......just cause it's Yew.
2006-10-10 03:22:22
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answer #1
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answered by Marianne not Ginger™ 7
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You have to dig deep to find the answer. I made a trunk call to a British mathematician and he said it depends on how many square knots are involved. Perhaps I am barking up the wrong tree and can't see the trees through the forest, but I think the answer is the radius of the foliage divided by pi ne squared. When in doubt always listen to your alders fir advice, and spruce up a bit. Remember what the acorn said when it grew up. "Geometry." What trees can do is beyond beleaf.
2006-10-10 06:56:56
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answer #2
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answered by Anonymous
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tricky question
root of a tree or square root of a tree/
(tree)^(1/2)
2006-10-09 23:03:10
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answer #3
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answered by Forrest T 1
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2(22/7* r*2){l}
2006-10-09 23:10:41
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answer #4
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answered by Raja 3
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I'm not completely certain, but I believe it involves a log function...
2006-10-09 23:11:52
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answer #5
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answered by Stephen F 2
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shovel + (trial + error) = 56(holes in yard)
Keep diggin until you find the one that isn't round.
2006-10-09 23:49:17
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answer #6
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answered by Antny 5
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you first take the derivative of the bark then solve for for 'axe' then graph function.
2006-10-09 23:04:15
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answer #7
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answered by st 3
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idk
2006-10-09 23:51:12
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answer #8
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answered by outrider 2
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