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8 answers

O(a)K ........we can figure this out together. Maple it out of my hat......but I'm determined to find this answer. It might not be the most Poplar answer, but even a Dog-wood not ignore this one.

Ok so.....give me a Pear of numbers and I'll conifer with my mathematical teacher friends and see what they can come up with. I knew I shouldn't just read all the time.......but it is so hard for me to branch out. But I'll go out on a limb this time.......just cause it's Yew.

2006-10-10 03:22:22 · answer #1 · answered by Marianne not Ginger™ 7 · 2 0

You have to dig deep to find the answer. I made a trunk call to a British mathematician and he said it depends on how many square knots are involved. Perhaps I am barking up the wrong tree and can't see the trees through the forest, but I think the answer is the radius of the foliage divided by pi ne squared. When in doubt always listen to your alders fir advice, and spruce up a bit. Remember what the acorn said when it grew up. "Geometry." What trees can do is beyond beleaf.

2006-10-10 06:56:56 · answer #2 · answered by Anonymous · 0 0

tricky question

root of a tree or square root of a tree/

(tree)^(1/2)

2006-10-09 23:03:10 · answer #3 · answered by Forrest T 1 · 0 0

2(22/7* r*2){l}

2006-10-09 23:10:41 · answer #4 · answered by Raja 3 · 0 0

I'm not completely certain, but I believe it involves a log function...

2006-10-09 23:11:52 · answer #5 · answered by Stephen F 2 · 0 0

shovel + (trial + error) = 56(holes in yard)

Keep diggin until you find the one that isn't round.

2006-10-09 23:49:17 · answer #6 · answered by Antny 5 · 0 0

you first take the derivative of the bark then solve for for 'axe' then graph function.

2006-10-09 23:04:15 · answer #7 · answered by st 3 · 0 0

idk

2006-10-09 23:51:12 · answer #8 · answered by outrider 2 · 0 0

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