I'm thinking a red wine would be best, but not really sure.
2006-10-06 13:21:08 · 34 answers · asked by Quin S 3 in Food & Drink ➔ Beer, Wine & Spirits
Honestly, I would go with a malbec - it's hearty eneough to match the gourmet sauce on the burger and whatever you may be dipping your fries in!
They're value based wines also, try trumpeter or punto final or alamos - they are all around 10 bucks.
great quesiton too by the way - with over 100 Billion getting served by ronalds crew, we should be able to BYO at those joints.
2006-10-06 13:23:59 · answer #1 · answered by Anonymous · 2⤊ 1⤋
Whopper for 5 motives a million. It tastes extra useful 2. this is bigger 3. IT does not have the bun in the midsection 4. It does not have that secret sauce 5. It has extra aspects and you will customize it extra
2016-12-08 09:48:33 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Thunderbird, Night Train or MD 20-20 should be proper.
2006-10-06 18:44:56 · answer #3 · answered by miyuki & kyojin 7 · 0⤊ 0⤋
reds not heavy light zinfandels or some good rose or banfi lumbrusco or any wine a good wine and this is the secret to good wine pick what you like to drink and use it for any time
2006-10-06 13:58:08 · answer #4 · answered by Anonymous · 0⤊ 1⤋
I'm actually leaning towards a slightly chilled chardonnay. It goes better with the saltiness of the fries.
2006-10-06 13:31:52 · answer #5 · answered by Ivan 5 · 0⤊ 1⤋
Trader Joes Two Buck
Port
Grape juice with some vodka.
2006-10-06 15:39:08 · answer #6 · answered by stigys 2 · 0⤊ 1⤋
Have you Trader Joe's where you are? I find a bottle of Two Buck Chuck goes with everything !
2006-10-06 13:22:13 · answer #7 · answered by Schleppy 5 · 0⤊ 0⤋
A nice chilled reisling. I've done it before! Fries + wine = good!
2006-10-06 13:22:47 · answer #8 · answered by yblur 5 · 2⤊ 1⤋
Boones. Runs about $2 a bottle.
2006-10-06 13:22:50 · answer #9 · answered by Lisa 6 · 1⤊ 2⤋
anything in a box if you're going to have McDonalds and winee together. Keep it cheap.
2006-10-06 13:22:39 · answer #10 · answered by crchase16 3 · 0⤊ 1⤋