How fast does the earth rotate in one minute?

Question

What is the formula? Is it possable to define this answer to at least 6 decmil places and what is unique about this question?

Answer 1

The rate of rotation doesn't change when the time-interval changes, just the distance covered and units-of-rotation. Please clarify your question so you get the answer you want.

The uniqueness of your question is that it is not really answerable, as you have phrased it.

The earth's circumference is 24,901.55. There are 1440 minutes in one day, so In one minute;

24901.55/1440 = 17.292743055555555555555555555556

So just a bit more than 17 miles of earth's equatorial circumference will rotate past an arbitrarily determined point, which is itself rotating around the sun. In MPH, this is 1037 miles/hour.


The circumference of the earth's orbit is approximately 584 million miles, and there are 365 X 1440 minutes in a year, or 525600 minutes. 584,000,000 / 525600 = 1111.11111... so in one minute, the earth covers approximately 1111 miles of it's annual trip around the sun. In mph, this is approximately 66666.6666.... miles/hour.

Answer 2

If you take earth's circumference to be 24250 miles then it revolves at a rate of 1,000 miles per hour. So in 1 minute it would rotate 1,000/60 = 16.666666 recurring miles.

The reason it is unique is because there is no whole decimal answer as it is a recurring number.

However on a more precise note:

What is the circumference of the Earth? How far around is the Earth?

The average radius of the Earth is 3,959 miles (6,374 kilometers).
The equitorial diameter of the Earth (distance from one side of the Earth to the other at the equator) is about 7,926 miles.


The ratio of the circumference to the diameter of a circle (circumference/diameter)
is written as the symbol pi.
Pi is approximately 3.141592.
3.14159265
3.1415926535


Therefore, to determine the circumference from the diameter given above:
equitorial diameter x 3.141592 = equitorial circumference
| |
7,926 x 3.141592 = 24,900
| |
The earth has a circumference of approximately 24,900 miles.


More precisely the circumference of the earth
at the equator is 24,902 mi / 40,076 km.


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How fast would you have to travel to see the sun set twice,
or outrun the shadow of the setting sun?

Since the sun "travels" once around the earth every 24 hours,
we can get the speed by dividing the circumference of the earth by 24:

miles divided by hours
| |
24,900 / 24 = 1,038 miles per hour



....

A RATIO of a to b can be expressed in three ways:
1. a : b
2. a / b
3. a ÷ b

Answer 3

You first have to define the rotation. Are you referring to the rotation of the earth about its axis, or the rotation of the earth around the sun? Two very different things would of course create two very different formulas.