i have two 22F 2.5 V capacitors which i want to power a 3.4V LED. i want to use all the power in the capacitors is their any way.
i have also conected the capacitors in series to get 5V from the capacitors and have to alter my resistance to get maximum light from the LED. help needed.
2006-10-03 21:36:42 · 2 answers · asked by 555 1 in Consumer Electronics ➔ Other - Electronics
nope - once they drain to the point where there is insufficient voltage to overcome the forward bias of the LED you are pretty much stuffed.
The theory of a system to overcome this would be to an oscillator to run a transformer to step the voltage up and then rectify it and use it as DC. hoever if you can't run a simple LED then you won't run an oscillator either!
2006-10-03 21:40:28 · answer #1 · answered by teef_au 6 · 1⤊ 0⤋
in case you quite have 2 22F capacitors you ought to use a voltage regulator circuit, sequence resistance (to regulate modern) and away you bypass. If even regardless of the undeniable fact which you have 2 22uF capacitors then you definately could desire to get a lot greater,connect them (2 in sequence) in parallel and stick to the above. suited of success. btw. word warning the present discharge from large capacitors could properly be deadly.
2016-12-26 09:06:10 · answer #2 · answered by purinton 3 · 0⤊ 0⤋