is it 76, 86, 96 or 136
2006-10-03 18:02:09 · 7 answers · asked by douglas d 1 in Science & Mathematics ➔ Engineering
I'm assuming it's a 4-inch diameter shaft (since that's the only assumption that leads to one of the choices of answers, and shafts/pipes are always measured by diameter).
Figure out the circumference first: 2pi r = 2(3.14)(2) = 12.56 inches
Change it to feet (since the problem is stated in feet):
12.56 inches / 12 = 1.04 feet
Now, divide 100 feet per minute by 1.05 feet to get revolutions per minute: 100/1.04 = (about) 96
2006-10-03 18:19:01 · answer #1 · answered by i_sivan 2 · 0⤊ 0⤋
RPM=?
12.56 inch = 1.046 666 667 feet
Diameter of a shaft=4 inch
Circumference=2*Pi*r=Pi*d=3.14*4=12.56 inch=feet
1 RPS=12.56 inch = 1.046 666 667 feet distance covered.
(1 RPM=1.046 666 667*60 feet distance covered=62.8FT Distance covered.)
so, for 100 ft/min
Required rpm=(100) feet/minute/(1.046 666 667) feet.
Required rpm=95.5414=96second^(-1)
2006-10-04 03:32:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The circumference of a circle = pi*diameter
12" = 1 '
100*12/(4pi) = ?
2006-10-04 01:33:40 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
My wife, just last night, stated the 4 inch shaft had a driving rpm force of "Oh my goodness!"
2006-10-04 01:03:36 · answer #4 · answered by Anonymous · 1⤊ 1⤋
HAHAHA!!
4 inch shaft...
Kudos for your winning of the internet...
2006-10-04 01:09:35 · answer #5 · answered by Tonx 3 · 0⤊ 0⤋
4 inch in diameter,radius or circumference?
2006-10-04 01:07:13 · answer #6 · answered by Lab 7 · 0⤊ 0⤋
Figure it out. Here is a hint: use pi
2006-10-04 01:04:32 · answer #7 · answered by doubletap_downzero 3 · 0⤊ 0⤋