Okay....you have numbers 1-25 to choose from...but each combination could only be used once...am I correct with the following eqaution?
25x24x23x22x21x20 = 127,512,000
2006-10-02 14:30:20 · 7 answers · asked by Lottery Guy 1 in Games & Recreation ➔ Gambling
Yes. It would be 25^6 if you could repeat numbers (which by the way would mean a 1 in 244,140,625 chance), but that is not what you have. So, you are correct: You have 25 numbers to select from for the first place, one fewer for the second place, etc... Hence your odds are one in 127,512,000, which is somewhat better than being allowed to repeat.
2006-10-02 14:37:59 · answer #1 · answered by Kay 2 · 0⤊ 0⤋
Yes, you are correct.
The odds of correctly picking the first number is 1 of 25, the odds of picking the second number is 1 of 24...
2006-10-02 14:38:39 · answer #2 · answered by TheSlayor 5 · 0⤊ 0⤋
If you have one bucket of 25 numbers then your answer is correct. If there are six buckets with 25 numbers in each, then it would 25 to the sixth power.
2006-10-02 14:45:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You should express it as one out of the number you calculated but it looks like your approach is correct. So it is 1/127,512,000.
2006-10-02 15:36:42 · answer #4 · answered by Rich Z 7 · 0⤊ 0⤋
It has been awhile...but I thought you multiplied the prime of those numbers. But...I have not taken a class on advanced mathematics in a while.
2006-10-02 14:40:01 · answer #5 · answered by Anonymous · 0⤊ 1⤋
It's easier than that -- it's 6 to the 25th power.
That's 28,430,288,020,000,000,000 to one.
2006-10-02 14:35:33 · answer #6 · answered by Anonymous · 0⤊ 0⤋
m
2006-10-02 14:33:25 · answer #7 · answered by Anonymous · 0⤊ 2⤋