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1.Create a Class OprOverload.

2.Class OprOverload should have a:
2.1.Constructor
2.2.Destructor
2.3.Methods to overload +, -, /, * operators

3.Conditions

3.1.+ = - ( + sign mean subtraction)
For e.g. 6 + 3 = 3

3.2.- = + ( - sign means addition)
For e.g. 6 - 3 = 9

3.3./ = * ( / sign mean multiplication)
For e.g. 6 / 3 = 18

3.4.* = / ( * sign means division)
For e.g. 6 * 3 = 2

2006-09-28 23:35:59 · 5 answers · asked by sack 1 in Computers & Internet Programming & Design

5 answers

This is really straightforward basic stuff in programming.

If you need help to do something like this while studying for a profession, then you are aiming for the wrong profession and you should really consider studying for a different one.

2006-09-29 02:23:44 · answer #1 · answered by TJ 6 · 1 0

Do your own homework. If you're having difficulty, search the net for C++ tutorials and references. If you're still having difficulty then speak to your lecturer. But NEVER ask someone else to do the coding for you. You can guarantee you will never learn anything about coding that way. Even if you get the qualification at the end of the course, if you cheat like this all the way through it will be a worthless scrap of paper at the end of it. The saddest thing is, you're only fooling yourself.

Oh, and we know what the mathematical symbols mean thanks, we went to school too.

Rawlyn.

p.s. Oh my word! I've only just noticed that you haven't even taken the question numbers off your homework!!! That's just plain LAZY dude!!!

2006-09-29 06:41:06 · answer #2 · answered by Anonymous · 1 0

I would tell ya, but when I was in school I got the answer from someone else, so I have no clue how to do it.

2006-09-29 09:36:30 · answer #3 · answered by justme 7 · 0 0

LoL Exactly what Rawlyn said if we help you, you will never get anywhere in life.

2006-09-29 06:59:07 · answer #4 · answered by Castor Troy 1 · 1 0

Yes.. if we help you .. that will be the most wired thing. We are not interested in blocking your future. :)

2006-09-29 07:31:48 · answer #5 · answered by NinethSense 3 · 1 0

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