x-3x√x
2006-09-28 19:49:40 · 6 answers · asked by Ironman123 1 in Science & Mathematics ➔ Mathematics
Rewrite as
x-3x*x^(1/2)
or
x-3*x^(3/2)
Now derivative using power rule:
1-(9/2)x^(1/2)
or
1-(9sqrt(x))/2
2006-09-28 19:52:45 · answer #1 · answered by Anonymous · 1⤊ 0⤋
let y = x - 3xâr
then taking derivative from both the sides,
dy/dx = 1 -[3(x*d/dx(âr) + âr*d/dx(x))] by using multiplication rule
dy/dx = 1 -[3(x*1/2âr + âr)]
dy/dx = 1 -[3(1/2âr + âr)]
dy/dx = 1 -(9/2âr)
2006-09-29 05:21:27 · answer #2 · answered by manoj 2 · 0⤊ 0⤋
Y=x-3xsqrtx
Y'=1-3[x*(1/2)x^-1/2+1*sqrtx]
=1-3[x/2sqrtx+sqrtx]
=1-3[x+2x]/2sqrtx
=1-9/2* x/sqrtx
2006-09-29 02:58:29 · answer #3 · answered by openpsychy 6 · 0⤊ 0⤋
1-9/2(x^1/2)
2006-09-29 03:51:07 · answer #4 · answered by khotl73 2 · 0⤊ 0⤋
Oops...... Pessimist was doing fine until he tried to simplify it.
It's 1 - (9/2)*âx âº
Doug
2006-09-29 02:59:34 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋
y=x-3x^1.5
y'=1-3*1.5x^.5=1-4.5sqrt(x)
2006-10-02 23:12:15 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋