1. If A and B are independent events with P(A) = 0.2 and P(B) = 0.6, thenP(A U B) =
2. A six sided die is tossed 3 times. The probability of observing three ones in a row is
2006-09-28 18:39:33 · 7 answers · asked by KISMET 2 in Science & Mathematics ➔ Mathematics
1. P(AUB) = P(A) + P(B)
2. P(1) = 1/6
P(1) & P(1) & P(1) = P(1) * P(1) *P(1) = 1/216
2006-09-28 18:42:39 · answer #1 · answered by holden 4 · 0⤊ 0⤋
1)P(A U B)=.2*.6=.12
2)Probability of observing three ones in arow=(1/6)(1/6)(1/6)=1/216
2006-09-28 19:52:32 · answer #2 · answered by openpsychy 6 · 0⤊ 0⤋
1.
The probability is 0.2+0.6 = 0.8.
2.
(1/6)*(1/6)*(1/6) = (1/216) = 0.004630
2006-09-28 18:44:09 · answer #3 · answered by Bramblyspam 7 · 0⤊ 0⤋
1. P(AUB)=P(A)+P(B)-P(A intersect B)
=0.2+0.6-(0.2)(0.6)
2. (1/6)^3=1/216
2006-09-28 20:57:38 · answer #4 · answered by khotl73 2 · 0⤊ 0⤋
2. (1/216)
2006-09-28 18:42:14 · answer #5 · answered by MateoFalcone 4 · 0⤊ 0⤋
1. 0.2*0.4+0.6*0.8+0.6*0.2=.68
2. 1/216
2006-09-28 18:41:58 · answer #6 · answered by need help! 3 · 1⤊ 0⤋
Trivia? Is this what you kids call homework nowadays?
2006-09-28 18:43:27 · answer #7 · answered by firat c 4 · 0⤊ 0⤋