Find a parametrization of the straight line segment which connects the point (-5, 2, 7) with the point (4, 5, -3). Substitution of t=0 should resolve to point (-5, 2, 7). Substitution of t=1 should resolve to point (4, 5, 6). Use t as the parameter or independent variable.
2006-09-28 17:08:32 · 4 answers · asked by Shane W 1 in Science & Mathematics ➔ Mathematics
donno
2006-09-28 17:13:40 · answer #1 · answered by Ashu 3 · 0⤊ 2⤋
"Substitution of t=1 should resolve to point (4, 5, 6)"
I'm going to assume you meant to write (4, 5, -3) there, since (-5, 2, 7), (4, 5, -3), and (4, 5, 6) are not collinear points. That said:
x=-5+9t
y=2+3t
z=7-10t
2006-09-29 00:12:24 · answer #2 · answered by Pascal 7 · 1⤊ 0⤋
Use vector addition to help you do it. Draw the vector locating the first point, then find the vector you add to it to get the second point.
(4,5,-3) +t (-9, -3, 10) will equal (-5,2,7) when t = 1
2006-09-29 00:16:55 · answer #3 · answered by z_o_r_r_o 6 · 0⤊ 0⤋
(-5+9t,2+3t,7-10t)
2006-09-29 00:12:00 · answer #4 · answered by bruinfan 7 · 1⤊ 0⤋