Suppose a hexagon ABCDEF (name). It has angles : - ABC, BCD, CDE, DEF, EFA and angle FAB. It also has six more angles the exterior ones! The sum of the six interior angles should be 360 degrees.
2006-09-28 17:05:37
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answer #1
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answered by Ashu 3
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Hello! Not sure I'll have time to work on this but at least wanted to say hi =) edit Proving that 126 is correct reduces to 4cos^2 18 = 4cos^2 36 + 1 which is true. The first point is to notice that if 1 the length of the sides, then FC = 2 cos 18. To see this just take the symmetric of B with respect to AC. Call G that point then BFG is equilateral and then all angles can be worked out. in particular CGF is isoscels in G with angles 18 18 144. Now since angles in CED are 108 36 36, in order to check that 126 = 90 + 36 works, you just need to show that CEF is a right triangle at E. This follows from 4cos^2 18 = 4cos^2 36 + 1 that is CF^2 = CE^2 + FE^2.
2016-03-26 22:13:41
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answer #2
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answered by Anonymous
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6 angles
2006-09-28 17:00:31
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answer #3
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answered by khotl73 2
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There are six (6) angles in a hexagon.
hexa- (or hex-) is a prefix from the Greek meaning "six".
2006-09-28 17:08:07
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answer #4
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answered by language is a virus 6
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6 angles 6 sides
http://mathforum.org/dr.math/faq/formulas/faq.regpoly.html#6
2006-09-28 17:38:50
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answer #5
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answered by Sherman81 6
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12 all together: 6 interior and 6 exterior.
2006-09-28 17:03:40
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answer #6
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answered by bruinfan 7
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SIX angles
2006-09-28 17:22:05
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answer #7
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answered by Nikki 2
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6?
2006-09-28 17:00:28
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answer #8
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answered by Anonymous
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i think it is six
2006-09-28 17:00:37
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answer #9
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answered by liljov2 2
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six
2006-09-28 17:05:23
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answer #10
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answered by Aly 2
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