Quiro and Jen are running in opposite directions around a 400 m track. Quiro runs at 3 meters per second and Jen runs at 5 meters per second. After meeting for their 6th time, how far will they be from the start line.
Show your work please.
2006-09-28 16:29:46 · 7 answers · asked by thrila_in_manilla 2 in Science & Mathematics ➔ Mathematics
for each second, they'll cover 3+5=8 meters. So it will take them 400/8=50 seconds to cover 400 m, or to "meet" for the first time.
50 seconds Jen would have run 50*5 = 250 meters.
When they meet for the 6th time, Jen would have run 250*6 = 1,500 meters.
At this instance, they will be 100 meters away from the start line (1,600 meters would have brought Jen full circle to complete 4 laps)
2006-09-28 16:42:45 · answer #1 · answered by boyjackie 2 · 1⤊ 0⤋
they keep meeting each other after 50 sec. so they meet the 6th time after 300sec. now consider jen. after 300 sec he will have travelled 1500m or he will be 100m from the line when he meets quiro.
2006-09-29 02:44:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3t+5t=400
t=50
Q: 150 m
J: 250 m
Distance Q has run after meeting J for 6 times =150*6=900 m
So Q is 100 m from start line(900-2*400=100).
2006-09-28 16:47:18 · answer #3 · answered by khotl73 2 · 0⤊ 0⤋
50 meters
2006-09-28 16:48:24 · answer #4 · answered by jdog44442003 3 · 0⤊ 0⤋
okay to write down ninety 4.a million% as a decimal only divide it via a one hundred to get carry of 0.941. a million/3% of sixty 9: multiply 0.3333333 repeated via sixty 9 to get your answer. one hundred is what % of 2 hundred: one hundred divided via 2 hundred and multiply via one hundred to get 50%. 12.3% of 87 is 0.123 expanded via 87. a hundred seventy five/.19 for the final one.
2016-10-18 04:21:08 · answer #5 · answered by oleyar 4 · 0⤊ 0⤋
Hi. Did they start at the start line?
2006-09-28 16:33:47 · answer #6 · answered by Cirric 7 · 0⤊ 1⤋
hint: find the NET speed to determine the time of meeting.
2006-09-28 16:34:08 · answer #7 · answered by Anonymous · 0⤊ 1⤋