The temperature at the summit of Mt. Mansfield dropped 17°F between 4 p.m. and 11 p.m. If the temperature at 11 p.m. was 11°F, what was the temperature at 4 p.m.?
2006-09-28 16:18:47 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
This is a simple subtraction problem.
If the temperature dropped 17 degrees F between 4pm and 11pm and was 11 degrees at 11pm, then the temperature at 4pm was:
X-17=11
or 17+11=X
X=28 degrees F
2006-09-28 16:22:58 · answer #1 · answered by merfie 2 · 0⤊ 0⤋
If the temperature dropped 17 degrees between 4 and 11 p.m, then it was 17 degrees higher at 4pm than it was at 11. So it should be 28 degrees.
Not so crazy!
2006-09-28 23:22:30 · answer #2 · answered by PatsyBee 4 · 0⤊ 0⤋
11+17=28
2006-09-28 23:21:39 · answer #3 · answered by Molly 2 · 0⤊ 1⤋
Simple buddy. here is how
Time 4 p.m. increase ----> 11 p.m
Temperature x dropped=17oF 11oF
Then x= 11 +17= 28 oF
Simple isnt it.
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2006-09-28 23:31:41 · answer #4 · answered by jugnu 3 · 0⤊ 0⤋
28
2006-09-28 23:21:53 · answer #5 · answered by jperk1941 4 · 0⤊ 0⤋
T1 - T2 = 17 F
T2 = 11 F
The times are extraneous.
T1-11 F = 17 F
T1 = 17 F + 11 F
2006-09-28 23:24:02 · answer #6 · answered by Helmut 7 · 0⤊ 0⤋
It was 11 degrees at 4 pm and dropped 17 degrees, so at 4 it was 17 degrees higher........28 degrees!!!
2006-09-28 23:22:39 · answer #7 · answered by divinestine 2 · 0⤊ 0⤋