Find first derivative of sin2 (cos x) ; and sin (sin x)?

Question

first quest : sin square (cos x)

sin ^ 2 (cos x)

Answer 1

1) y= (sin(cosx))^2

dy/dx = 2 (sin(cosx)) (cos(cosx)) (-sinx) = -(sinx) (sin(2cosx))

2) y = sin (sinx)

dy/dx = (cosx) (cos(sinx))

Answer 2

first question is not clear

for the second one use function of function rule

if y = sin (sin x)

dy/dx = cos(sinx) * cos (x)


for the first question if you mean y = sin (2 cos x)

dy/dx = cos(2 cos x) * { -2 sin x}

Answer 3

i LOVE calculus, you should have asked me this years earlier...

bad news...cant find my book, either way its an easy problem from when i recall. the only thing i remmeber by heart was that the derivative of sinx was -cosx and cosx was sinx. hope that helps :)