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plzz help and give formula too

2006-09-28 12:56:56 · 3 answers · asked by hiba 1 in Science & Mathematics Physics

3 answers

You can use 4000N for anindefinite time and raise the load to anindefinite height.In practice time is required, which you missed to supply. Nevertheless, assuming time is involved we can calculate the height as follows:
F=m*a-m*g, since it is raising against gravity and the mass moves at a certain acc. a.
F= m(a-g)
a=F/m +g
a=4000/30+10
a=143.3 m/s^2 (!)
h=0.5*a*t^2
h=0.5*143.3*t^2
h=71.65*t^2
You can insert any time in seconds and get your height. For example the height in 2 and 5 seconds will be:
h(t=2) =71.65*2^2
h(t=2) =286.6 meters
h(t=5) =71.65*5^2
h(t=5) =1791.25 meters.

2006-09-28 23:36:19 · answer #1 · answered by mekaban 3 · 0 0

This is a highly flawed question. If F = 4,000 Newtons, I can raise about 300 N weight an indefinite height. All I have to do is indefinitely continue to apply that 4,000 N to the body of m = 30 kg. In fact, as you get higher away from the surface of the Earth, the weight (W = mg) of your 30 kg mass will decrease, making it easier for that 4,000 N of force to lift the mass even higher.

We can see this in f = F - W; where F is your 4,000 N and W = mg = 30 kg X 9.81 m/sec^2 ~ 300 N. As long as F > W, f the net force on the mass will be positive (upward), away from the surface. It will continue to rise. Further, as the mass gets farther away from the surface W --> 0, the weight gets lighter. So F >>> W as we leave the Earth. As a result, the mass will accelerate even more at higher (greater) distances from Earth.

2006-09-28 13:13:36 · answer #2 · answered by oldprof 7 · 0 0

(assume g=10) mass=force/gravitational force,so 4000N/10=400kg......400kg+30kg=430kg.....equal to 400kg raise....

2006-09-28 13:02:09 · answer #3 · answered by Anonymous · 0 1

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