Hi. Depends on the diameter. If the second hand was large enough the speed could get up to c, the speed of light.
2006-09-28 11:28:13
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answer #1
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answered by Cirric 7
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Since you added that the second hand is 1 inch long, I'm assuming you are trying to get to the speed at it's outer point. So, you have a circle with a radius of 1 inch. The circumfrence, then is 2(pi)r=6.28 inches. Since it travels that distance in 1 minute, it would go 60(6.28) inches/hour, or 376.8 inches/hr. I'll let you convert that many inches/hr into miles/hr.
2006-09-28 11:35:22
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answer #2
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answered by hcbiochem 7
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Yeah, unfortunately there is NOT an answer for your question. Even though you mention that the hand is one inch long, the outer tip of the hand is moving much faster than the part closest to the center of the watch--if you just pinpoint one specific point on the hand, then your question becomes a great one--with an answer.
2006-09-28 11:34:58
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answer #3
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answered by pocket68rocket 4
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Determine the diameter of the watch
Circumference = diameter x Pi
You know the watch goes that far in 1 minute.
Multiply by 60 minutes
Convert that to miles (5280 feet in a mile. 12 inches in a foot)
Example:
Watch is 2 inches across in diameter
Circumference is approx. 6.28 inches
6.28 inches per minute is the speed
376.8 inches per hour
376.8 inches divided by (5280 x 12)
0.00595 miles per hour
2006-09-28 11:35:02
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answer #4
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answered by ADF 5
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The speed is 2 * PI * R / 12h you need to convert that into miles / hour if I am correct at asuming the second hand wil be the small one ?
2006-09-28 12:17:21
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answer #5
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answered by HurricaneHarry 1
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one second every second
2006-09-28 11:27:50
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answer #6
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answered by iMegan 3
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well, you didn't say how long it was, so all I can say is, 0mph at the base.
2006-09-28 11:28:06
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answer #7
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answered by holden 4
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