If my friends truck does 0-60 MPH within 900 Ft, and mine does 0-60 in 10 sec..?

Question

How many seconds does it take for my friend to do 0-60 MPH?

Answer 1

To find answer you must apply this physics formula:

distance=speed X time

data:

distance= 900 feets
speed = 60mph
time = ?


We have: distance = speed X time

time = distance/speed

= 900 feets/60mph

= 15 seconds

Answer : 15 seconds

Answer 2

Michael E is correct. We truly don't know if acceleration is constant or not, thus we would need to know the function of acceleration and integrate accordingly.

However ...

This is pretty simple if you assume constant acceleration.
Use the standard equations of motion.

The two i will use are

v_f^2 = v_0^2 + 2ax

and

v_f = v_0 + at


1.
First we must convert to a common unit system. I'm going to use ft and seconds as my standard distance and time measurements. You really could use anything you want.

0 MPH = 0 ft/s
60 mph = 60*(5280ft/3600s) = 88 ft/s

v_0 = 0 ft/s
v_f = 88 ft/s

2. Using newtons equations

88^2 = 0^2 + 2*a*900 ft

solve

a = 4.302 ft/s^2

3. Using the second equation

88 ft/s = 0 ft/s + 4.302*t

solve for t

t = 20.46 seconds *** answer***

Answer 3

Apples and oranges my friend. You cannot calculate time into distance or vice versa with the info provided.....

Using the example above mine - is your truck really more than twice as fast as your friends? I doubt it....

Answer 4

You cannot answer that question with the information you have provided.

Update:

@polloloco: You are assuming constant acelleration.