Hi again;
(e)^ [(ln3/3)]^6
As you know ln(1) = 0 & any number power Zero is 1 ; { if a is a real number so a^0 = 1 }
Step1;
3/3 = 1 so ; ln(3/3) = ln 1 = 0
Step 2;
0 ^6 = 0
Step 3;
e^0 = 1
so ;
(e)^ [(ln3/3)]^6 = 1
Good Luck....
2006-09-30 07:53:41
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answer #1
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answered by sweetie 5
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1
=)
2006-09-28 11:09:11
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answer #2
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answered by يا حسين 4
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3/3 = 1
ln(1) = 0
0^6 = 0
e^0 = 1
2006-09-28 11:08:32
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answer #3
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answered by Dimos F 4
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I agree with Dimos
Answer is 1
2006-09-28 11:22:14
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answer #4
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answered by Nani 2
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i think the e and ln cancel out leaving (3/3)^6 which gives u 1
2006-09-28 11:10:47
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answer #5
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answered by ynroh 3
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e does nothing to ln so its not that its out negative 3 so its (3/9) ^88% neagtive 3 i had this problem and i got an A
2006-09-28 11:09:23
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answer #6
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answered by luvabout 1
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Go on yahoo.com, and put homework helpline, and press search, and just look through all of them until you find one that can help you. Or look in your textbook and there is always a website in your textbook... Good Luck!
2006-09-28 11:12:14
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answer #7
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answered by mk 1
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Wouldn't it be a lot easier for you to look it up in your math book rather than waste your time on here?
2006-09-28 11:08:02
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answer #8
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answered by Anonymous
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i have worked every type of job, and that problem never came up. you will never need to know it, unless you become a math teacher.
2006-09-28 11:10:55
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answer #9
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answered by Anonymous
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Answer is 1!
2006-09-28 11:10:14
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answer #10
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answered by Vladimir 1
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