Suppose an antelope runs a distance of 5.0km in a direction 11.5 degrees north of east, turns, and runs 1.0km south. Calculate the resultant displacement.
2006-09-28 10:51:28 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Hmmm..
I assume you have said 5km with an angle of 90-11.5 = 78.5
And the 1 km at 270
We have to breakdown into vector components and then add algebraicaly these components:
1. -- D1y=5sin(78.5)=4.9 km (East)
2.--D1x=5cos(78.5)=.997 km (North)
3.--D2y=-1 km (South)
4.--D2x=0
Dx=.997
Dy=4.9-1=3.9
The resultant vector is D
D=sqrt(Dx^2+Dy^2) (Pythagorean theorem )
D=sqrt(16.2)=4.025 km
Angle = arctan(Dy/Dx)=arctan(3.9/.997)=
Angle =75.7 degrees
The resultant is 4.025 km 14.3 degrees north of east (based on your convention)
I hope it helps
2006-09-28 10:59:28 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
Draw the vectors tip to tail, then draw the resulting displacemtns vecor, and use the pythegorean theorem in its extended version (Asquared = Bsquared + Csquared - 2bc cosa) to calculate the distance.
2006-09-28 17:55:46 · answer #2 · answered by Ray B 2 · 0⤊ 0⤋
NO, but I can show you how to google
didn't you learn Pythagoras theorem in 10th grade?
A SQ PLUS B SQ IS C SQ
2006-09-28 17:58:59 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Bigger than a taco. Smaller than a planet.
2006-09-28 18:15:42 · answer #4 · answered by outlaw_tattoo_biker 4 · 0⤊ 0⤋
You can solve this graphically with a ruler and protractor.
2006-09-28 18:18:07 · answer #5 · answered by daedgewood 4 · 0⤊ 0⤋
Do your homework alone
2006-09-28 17:55:04 · answer #6 · answered by Nani 2 · 0⤊ 0⤋