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Presuming you're talking about n-butyl alcohol, it will be CH3CH2CH2CH2OH, which will then be oxidized to butanal, CH3CH2CH2CHO, before ending up as butyric acid, CH3CH2CH2CO2H.

2006-09-28 10:47:53 · answer #1 · answered by TheOnlyBeldin 7 · 1 0

butyl alcohol?
C4H9OH...

2006-09-28 17:47:09 · answer #2 · answered by kb27787 2 · 0 0

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