How is it that "g" is not constant everywhere on the surface of the earth?

Answer 1

i see that all the previous answers have missed your point.

you are correct in that "g" is NOT constant everywhere on earth. ( not to be confused with "G" the gravitational constant ).

there are 3 reasons for this:

1. "g" varies with the distance of the object from the center of the earth. ( not all points are equi-distant from the center ).

2. the earth has varying density ( non uniform ) and the gravity varies with density.

3. centrifugal force due to the earth's rotation counters its gravity "experienced" at the equator ( objects weigh less at the equator ). in this case, the actual value of g doesnt change but the manifested acceleration because of gravity will be less.

i tried to answer your question as thoroughly as i could !

:)

Answer 2

The density of Earth is not perfectly uniform, and the shape of Earth is not perfectly spherical. So 'G' would be higher over, for example, a very dense ore body or in a deep valley; it would be lower over a large gas field or at the top of a mountain (where you are simply farther from the centre of the Earth).

Geologists use the distortions of satellite orbits and other sensitive accelerometers to find interesting subterranean features. It's a sneaky way to peek under the surface!

Answer 3

the answer to the 1st question is definite (the the style of digits to the main appropriate of the decimal in the numerical fee representing the version in rigidity is previous something scientist have been waiting to instruct above hypothesis and concept) 2d Q: The rigidity of gravity is only between the climate that has effects on the speed of a falling merchandise. Weight, density, length, drag (aka wind resistance) are all actual factors that impact the fee or terminal speed of a falling merchandise. on each and every occasion anybody speaks of a feather or piece of paper falling on a similar fee as a rock or bowling ball, they're assuming none of those forces different than gravity are latest (i.e. the test is occurring in a vacuum)

Answer 4

g is an acceleration, so it must be associated with a force,

F = ma or F = mg

Hence g = F/m

F in this case is the force exerted by the Earth's Gravitational field, and is given by,

F = GMm / r^2 (r^2 is r-squared)

G = Gravitational constant
M = mass of Earth
m = mas of object on Earth.

or

g = F/m = GM / r^2

g = 9.81 m/s^2 is associated with Sea-level assuming a perfectly spherical, uniformly dense Earth. As you move around on the Earth, slight variations in F due to altitude, the non-spherical shape of the Earth, and density variations cause slight variations in g.

Answer 5

"g" is the result of the gravitational attraction of masses. Any mass with have a gravitational effect. Therefore, the amount of masses nearby affect the value (and direction) of g on earth, even though the value is predominantly determined by the mass of the earth. It is known that near a large mountain, g is not directed exactly toward the center of the earth.

Answer 6

The earth is not a perfect sphere. Some points are closer to the center of mass than other and so will have more gravity exerted them, but the difference really is negligible.

Answer 7

because gravity obeys the inverse square law. therefore decreasing with increased altitude or distance from the center of a planet.

Answer 8

g being the acceleration due to gravity...One reason is the height above sea level

Answer 9

G as in Gravity?

Answer 10

"E" overrides "G" thus making "G" inconsistent. Always refer to "E" in your mathematical equations.