Find an equation of the tangent line to the curve at the given point.?

1 ⤊

y = (e^x)cos(x) , point (0,1)

2006-09-28 07:55:34 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

dy/dx=(e^x)cosx-(e^x)sinx
==>m=1
==>y-1=x
==>y=x+1

2006-09-28 08:00:44 · answer #1 · answered by Mamad 3 · 1⤊ 0⤋

You have the point, so now find the slope. Find dy/dx, at x = 0, and that's your slope. Now use the point-slope formula.

2006-09-28 14:59:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋

dy/dx=e^x(-sinx)+cosx(e^x)
at (0,1)
dy/dx=1
equation=y-1=x
e^x(cosx)-1=x

2006-09-28 15:04:35 · answer #3 · answered by raj 7 · 0⤊ 0⤋

you have to calculate y' and then you replace by the point.

2006-09-28 14:58:33 · answer #4 · answered by pandora_cat 2 · 0⤊ 0⤋