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i have the answer x = 0 but im not sure if this is correct

2006-09-28 07:47:45 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Because the intercepts are also the zeroes or roots, let y = 0 and solve. The equation becomes 0 = x^2 - 1, where ^2 means "squared". This can be solved one of two ways. One, extraction of roots. Add 1, and get x^2 = 1. Therefore, x = +/- sqrt(1), where +/- means plus-or-minus, or in other words, in this case, positive or negative; and sqrt means "square root". Thus, x = +/-1, i.e. either 1 or -1.

Solution two. From x^2 - 1 = 0, conclude by factoring that (x + 1)(x - 1) = 0. By the Zero Product Property, either x + 1 = 0, or x-1 = 0. Solving both, either x = -1, or x = +1, respectively--the same solutions to method one.

hope this helps

2006-09-28 07:56:13 · answer #1 · answered by Anonymous · 0 0

Rearrange your equation so it reads y = x2 - 4x - 5. The x-intercepts are the criteria the area the graph crosses the x-axis. In those aspects, y = 0, so x2 - 4x - 5 = 0. Now, the inelegant approach is to truthfully plug the values given for A, B, C, and D to analyze it really is the entire perfect answer, it really is, replace "x" contained contained in the equation with the first value contained contained in the parentheses (in the previous the comma) and note if the right effect's = 0. (0 would favor to also be the 2d value contained contained in the parentheses, after the comma, which guidelines out B.) the added ideal stylish approach is to locate an expression like (x - a)(x - b) = x2 - (b+a)x +ba = x2 - 4x - 5. If ba = -5, and (b+a) = 4, an obtrusive answer is a = 5 and b = -a million. as a results of the indisputable fact that if (x - a) = 0 or (x - b) = 0 the entire expression equals 0, the values for a and b are also the x-values on your x-intercepts. it really is about so a lengthy way as i visit flow without telling you no matter if it somewhat is a, B, C, or D.

2016-11-25 00:58:19 · answer #2 · answered by kuhns 4 · 0 0

That's actually not correct. You find the x intercepts by setting y equal to zero. You need to solve the fairly simple quadratic equation x^2 - 1 = 0. Zero is not a solution to that equation, because 0^2 - 1 = -1, not 0.

2006-09-28 07:50:24 · answer #3 · answered by DavidK93 7 · 1 0

To find the x-intercepts of a graph, y must be zero.
y=x(squared)-1
0=x(squared)-1 Add 1 to both sides.
1=x(squared) Rewrite using the reflexive Property
x(squared)=1 Take the square root of both sides.
x=positive 1 or negative 1

2006-09-28 08:17:01 · answer #4 · answered by mom 7 · 1 0

It's a function! Start plugging numbers into x and you will get the intercepts yx. So if x=2 y=3...understand rubber-band?

2006-09-28 07:52:33 · answer #5 · answered by Perry L 5 · 0 2

x-intercepts
happen when
y=0
in this case
x^2-1=0,
so x^2=1
so x=1 or x=-1

so your answer x=0 is WRONG

2006-09-28 07:54:37 · answer #6 · answered by Anonymous · 1 0

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