Differentiate. g(t) = 4 sec(t) + tan(t)?

0 ⤊

2006-09-28 07:40:48 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

dg/dt = 4 d/dt(sec t) + d/dt(tan t)
= 4 sec t tan t + sec ^ 2 t using derivatives of standard trig functions

2006-09-30 04:37:01 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋

What's the derivative of sec(t)? Multiply that by 4. What's the derivative of the tangent function. Add that.

2006-09-28 07:48:34 · answer #2 · answered by Anonymous · 0⤊ 0⤋

g'(t)=(1+4sint)/(cost)^2

2006-09-28 08:44:14 · answer #3 · answered by Mamad 3 · 0⤊ 0⤋