how many moles of ions are in 27.5 g of mgcl2?

Question

I m a student

Answer 1

To do this, find how much 1 mole of MgCl2 would mass.
MgCl2 = 1 atom of Mg (24) and 2 atoms of Cl (35) = 94 g/mol

Then, divide the mass of the compound by the number of grams/mole.
27.5 g / 94 g/mol = 0.293 moles

Answer 2

first of all which ions do you want? the formula weight for mgcl2 would be 1mol mg(24.30amu)+2mol cl(35.45)=95.2g/mol. So divide the grams of mgcl2 by the formula weight so (27.5g) mgcl2/(95.2 g/mol) mgcl2=.2888866 moles of mgcl2, now to get the moles of mg you would have to multiple by 1mol mg/1mol mgcl2 to get .288866 moles of mg2+ ions, and to get cl- ions you would multiple .288866 moles mgcl2 by 2 mol cl-/1 mol mgc2 to get .57731 moles of cl- ions.

Answer 3

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