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if you think you can , try drawing the shapes and you will find out 4 is the most number of shapes taht can all share a border with all the other shapes. If u think 5 shapes is possible i would like to see it proven.

2006-09-28 07:19:16 · 3 answers · asked by dav4321k 1 in Science & Mathematics Mathematics

3 answers

Of course it's impossible (at least on the plane). It's merely another way of stating the four-color theorem.

2006-09-28 08:22:32 · answer #1 · answered by Pascal 7 · 0 0

As Pascal said, it can't be done in a plane, at least a Euclidean plane. In a plane of an elliptical space (the surface of a globe, for instance) you can do it by cutting the globe into four quadrants and sticking a fifth area at one the intersections. I think they've figured out how to get six or seven on a torus (doughnut).

2006-09-29 12:01:19 · answer #2 · answered by cdmillstx 3 · 0 0

Try a pentagon or hexagon. You can draw 7 hexagons and 6 can border the 7th/ center one perfectly.

2006-09-28 07:34:49 · answer #3 · answered by tigerzntalons 4 · 0 1

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