333
424
882
106
2006-09-28 06:49:38 · 12 answers · asked by sweetness01201 2 in Science & Mathematics ➔ Mathematics
882
Now how you can find out:
6=2*3
Therefore,it must be multiple of 2 and 3
The number is multiple of two if the last digit divides by 2(0,2,4,6,8)
And the number is multiple of 3 if the sum of all the digits divides by 3
882->the sum is in this case 8+8+2=18:3=6
2006-09-28 06:54:52 · answer #1 · answered by ioana v 3 · 2⤊ 0⤋
The answer is 882, but you don't need a calculator to figure it
333 is odd so you can rule it out immediately. there are no odd multiples of an even number.
424=420+4.
420 is divisible by 6 but 4 is not so 420 is not a multiple.
106=(6x17)+4
Again, 102 is a multiple of 6 but 4 is not.
Divide 882 by 6 you get 140 +42/6=140 +7=147
6x147=882 so you know this is correct.
2006-09-28 07:19:57 · answer #2 · answered by True Blue 6 · 0⤊ 0⤋
To find a multiple of six, first it has to be an even number (2 is a factor), then the digits have to add up to a number that is divisible by 3 (3 is also a factor).
333 no, 424 no, 882 yes, 106 no
2006-09-29 07:09:51 · answer #3 · answered by mom 7 · 0⤊ 0⤋
882
2006-09-28 06:58:49 · answer #4 · answered by flip103158 4 · 0⤊ 0⤋
882
2006-09-28 06:56:53 · answer #5 · answered by judy_r8 6 · 0⤊ 0⤋
882
2006-09-28 06:51:25 · answer #6 · answered by natarajan@ezee 2 · 0⤊ 0⤋
882 is a multiple of 6. It is even and its digits sum to 18,
which is a multiple of 3. Actually, it is even and a multiple
of 9, so a multiple of 18.
2006-09-28 07:02:26 · answer #7 · answered by steiner1745 7 · 0⤊ 0⤋
882 because the sum of all 3 numbers add upto multiple of 6
2006-09-28 06:58:52 · answer #8 · answered by Anonymous · 0⤊ 0⤋
A multiple is a number that can be divided by in this case 6 without leaving a remainder. Do the simple division to figure it out.
2006-09-28 06:58:05 · answer #9 · answered by Melius 7 · 0⤊ 0⤋
882 is a multiple because its the only one that divides evenly-147 times
2006-09-28 06:53:06 · answer #10 · answered by valerie_moore.t21@btinternet.com 2 · 0⤊ 0⤋