Imagine a cube, each edge of which is a 1 ohm resistor. What is the resistance across diagonally opposite corners?
2006-09-28 06:18:56 · 3 answers · asked by charlie 2 in Science & Mathematics ➔ Physics
The first answer given below is soo way of the mark. suggest you go back to basic electronic theory and start again.
I am not really after an answer to this. I set it as a puzzle so the answer below of building it is not much use to me and would also be very difficult to ensure exact ohmic values. Keep the answers coming, I will post the exact answer soon.
2006-09-29 22:35:39 · update #1
That's a really complex resistor network and I can't do the maths.
2 days later...
I think you have to break it down into 3 identical parallel circuits, calculate the resistance of one circuit
which is 1 ohms in series with (2 ohms in parallel with another 2 ohms) = 2 ohms total
3 of those in parallel = 1/R = 1/2 + 1/2 + 1/2 = 0.6666 ohms
It's hard to explain without a diagram...
2006-09-28 06:36:12 · answer #1 · answered by Henry 5 · 0⤊ 0⤋
The path of least resistance from one corner to the diagonally opposite corner is through 3 sides. Each side has a resistance of 1 ohm. The path is serial (one after the other) so the total resistance is 3.
2006-09-28 13:22:57 · answer #2 · answered by DanE 7 · 1⤊ 0⤋
Why not buy 12 one ohm resistors and connect like a cube then use ohm meter to measure the equivalent resistance.
2006-09-29 15:05:31 · answer #3 · answered by dwarf 3 · 0⤊ 0⤋