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y<2
2x + 3y <6

My problem is not so much the equation, it is locating the quadrant to begin x-y ?

2006-09-28 05:21:33 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

y < 2
2x + 3y < 6

take that and go to www.quickmath.com, click on Graph under Inequalities, and this will give you your graph.

you should get a graph of y < 2 with x having infinite solutions.

2006-09-28 08:00:41 · answer #1 · answered by Sherman81 6 · 0 0

where ever there is a < or > inset an = the 2x+3y<6 becomes 2x+3y=6 find either x or y then substitute it. y<2 means to goto 2 on the y axis.

2006-09-28 12:32:21 · answer #2 · answered by ♥will♥skate♥4♥life♥ 4 · 0 0

Begin in 1st quadrant.

2006-09-28 12:31:19 · answer #3 · answered by ag_iitkgp 7 · 0 0

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