For loop for(int i=0;i<10;i++){ }?

Question

for(int i=0; i<10; i++)
{

printf("----------");

}

The initialize statement is ended with ";" so is the condition but the incerement is not terminated,
So its a Expression and C compiler takes only Statement's but still it works without showing any ERROR...!!!!
Why is it???

Answer 1

u have a good question to create trouble amongst C litrates .. but i have a good explanation and its not just my thinking ..

first of all, as u know 'for' is not a function, so there is no question of arguments. for is a construct and it is not being broken in to 3 different statements, as u said
int i=0; is a statement .. then what about i<10; will this be treated as statement by the compiler?
if no then how can i++ (in a for construct) be treated as statement. if it is treated so then it should be i++;, then u r right..but no it is not treated as seprate statements but the whole construct is internally interpreted ... here ; is used just to seprate the 3 different things needed for a for construct and not taken as termination character. again if u say int i=0; is interpreted as a statement then for loop should have to terminate just after initialization of statement ..whice is not the case.

one more thing ....

have u seen the if - else conditional construct. ...

what happened if i do this ..
int i=0;
if(i==0)
{
printf("\n I m inside the IF construct bcoz i is equal to 0");
}

now see this ...
int i=0;
if(i=2)
{
printf("\n I m inside the IF construct bcoz i is assigned 2");
}
// here i have used "i=2" (assigned 2 to i) and not "i==2".
ok now here u can see "if(i=2)" is an assignment statement .. but have i placed a ; over there ... ? like this if(i=2;)
but still if(i=2) will work.

i hope u r satisfied with this answer.
if u still have any problem regarding this u can send me message

Answer 2

actually, that is the proper syntax for a for loop, so why would it give you an error?
the compiler sees the "for" keyword and knows that it needs to set up a loop based on the other parameters (that are separated by semicolons).
what the compiler would do with your example is to initialize a internal register to 0, compare it with 10, execute the printf statement, increment the register and loop back to where it compares it with 10.

Answer 3

To be honest, I never really thought of it much. It may be that the compiler treats each of those three expressions as inputs to a function "for" (internally, I mean), and so those are just arguments.

Not a bad question, but I expect that a complete answer would have to get knee-deep in compiler inner workings.

Answer 4

the syntax here is:

statement :=
for(;
;
)

The whole loop is a single statement.

Answer 5

as far as i know
the syntax of a for statement contains
1.the initialisation
2.a condition
3.the increment
these three are SEPARATED by semicolons
thats it

Answer 6

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