how mush would an electron weigh if it were accelerated to 90% the speed of light.?

Answer 1

This depends whether you're talking about its rest mass (invariant mass) or its relativistic mass. The latter is computed as M = m*(lorenz factor), where m is the rest mass (in the case of an electron, 9.11e-31 kg). The Lorenz factor is 1/sqrt(1-u^2/c^2). In your example, this is 1/sqrt(1-(.9c)^2/c^2) = 1/sqrt(0.19) = 2.29. So the relativistic mass would be rest mass * 2.29.

Answer 2

According to the laws of thermodynamic motion does come with paying a price. Therefore for the electron to increase in velocity from 4.19 x10^5 meters per second to 90% C the speed of light it has to pay a price in terms of its structural energy. To do that it must lose mass.ThereforeThe power applied to move the electron at that speed would cause the electron to lose 56.41101056 per cent of its mass.

The results would leave the electron with a mass of
3.9706914 x10^-31 kilograms.

Its weight would be at sea level equal to;
3.89391705 x 10^-30Newtons.

To convert it back to its original weight the electron has to slow down to its original velocity. In the process it will absorb 56.411% of its original mass from its surroundings .So its normal mass as a free electron would be back to 9.109389700 x10^-31 kilos.

Answer 3

mass of an electron m0 = 9.10938188 x 10^-31 kg

relativistic mass mr = m0 /sqrt(1-v^2/c^2) =
9.10938188 x 10^-31/sqrt(1-0.9^2) =
9.10938188 x 10^-31/sqrt(1-0.81) =
20.9 x 10^-31 kg (approx)

Answer 4

Its normal weight times 1/sqrt(.19)= or 2.29 times its normal weight.

Answer 5

why don't you use the gamma factor to find it. you would get the correct answer. try it. and this answer is the best answer. the change would nopt be so much because it's masss is almost negligible